The geometry,hybridization,and magnetic momen | vedclass

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(D) $CN^-$ is a strong field ligand,while $Br^-$ and $F^-$ are weak field ligands.For $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ has $d^8$ configuration. $CN^-$ caus

Vedclass · Accepted Answer

Square planar,tetrahedral,octahedral : $dsp^2, sp^3, sp^3d^2 : 0, 5.9, 4.9$

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(D) $CN^-$ is a strong field ligand,while $Br^-$ and $F^-$ are weak field ligands.For $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ has $d^8$ configuration. $CN^-$ causes pairing,leading to $dsp^2$ hybridization (square planar) with $0$ unpaired electrons and $\mu = 0 \ BM$.For $[MnBr_4]^{2-}$,$Mn^{2+}$ has $d^5$ configuration. $Br^-$ is a weak ligand,leading to $sp^3$ hybridization (tetrahedral) with $5$ unpaired electrons and $\mu = \sqrt{5(5+2)} = 5.9 \ BM$.For $[FeF_6]^{4-}$,$Fe^{2+}$ has $d^6$ configuration. $F^-$ is a weak ligand,leading to $sp^3d^2$ hybridization (octahedral) with $4$ unpaired electrons and $\mu = \sqrt{4(4+2)} = 4.9 \ BM$.

List-$I$	List-$II$
$(1)$ $dsp^2$	$(A)$ $BrF_5$
$(2)$ $sp^3d^2$	$(B)$ $[Co(NH_3)_6]^{3+}$
$(3)$ $sp^3d$	$(C)$ $[PtCl_4]^{2-}$
$(4)$ $d^2sp^3$	$(D)$ $PCl_5$

The geometry,hybridization,and magnetic moment of the ions $[Ni(CN)_4]^{2-}$,$[MnBr_4]^{2-}$,and $[FeF_6]^{4-}$ respectively are:

Similar Questions

Match the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$.

List-$I$ List-$II$

$(1)$ $dsp^2$ $(A)$ $BrF_5$

$(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$

$(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$

$(4)$ $d^2sp^3$ $(D)$ $PCl_5$

Which of the following statements is incorrect?

Which set of $d-$ orbitals is used by the central metal during the formation of $MnO_4^-$?

The complex ion $[Cu(NH_3)_4]^{2+}$ has which of the following geometries and electronic configurations?

Cobalt chloride when dissolved in water forms a pink-colored complex $X$ which has an octahedral geometry. This solution,upon treatment with concentrated $HCl$,forms a deep blue complex $Y$ which has a $Z$ geometry. $X$,$Y$,and $Z$,respectively,are:

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